Given ∫01f(x)dx=3\int_{0}^{1} f(x) dx = 3∫01f(x)dx=3 and ∫01g(x)dx=−1\int_{0}^{1} g(x) dx = -1∫01g(x)dx=−1, find ∫01(2f(x)−3g(x))dx\int_{0}^{1} (2f(x) - 3g(x)) dx∫01(2f(x)−3g(x))dx.
333
999
666
000