Given f(x,y,z)=x2+2y2+3z2f(x, y, z) = x^2 + 2y^2 + 3z^2f(x,y,z)=x2+2y2+3z2, find the directional derivative at (1,1,1)(1, 1, 1)(1,1,1) toward the point (2,3,4)(2, 3, 4)(2,3,4).
2014\frac{20}{\sqrt{14}}1420
1014\frac{10}{\sqrt{14}}1410
202020
14\sqrt{14}14