Given f(x,y)=x2yf(x, y) = x^2 yf(x,y)=x2y, find the Hessian matrix at (1,1)(1, 1)(1,1).
(2220)\begin{pmatrix} 2 & 2 \\ 2 & 0 \end{pmatrix}(2220)
(1221)\begin{pmatrix} 1 & 2 \\ 2 & 1 \end{pmatrix}(1221)
(0222)\begin{pmatrix} 0 & 2 \\ 2 & 2 \end{pmatrix}(0222)
(2002)\begin{pmatrix} 2 & 0 \\ 0 & 2 \end{pmatrix}(2002)