Given f(x)=∑n=0∞(−1)nx2n+1(2n+1)!f(x) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!}f(x)=∑n=0∞(2n+1)!(−1)nx2n+1, evaluate f(5)(0)f^{(5)}(0)f(5)(0).
111
−1-1−1
1120\frac{1}{120}1201
000