Given f(x)=∑n=0∞anxnf(x) = \sum_{n=0}^{\infty} a_n x^nf(x)=∑n=0∞anxn has radius of convergence R=4R=4R=4, find the radius of convergence of g(x)=∑n=0∞an2xng(x) = \sum_{n=0}^{\infty} a_n^2 x^ng(x)=∑n=0∞an2xn.
Rg=2R_g = 2Rg=2
Rg=4R_g = 4Rg=4
Rg=8R_g = 8Rg=8
Rg=16R_g = 16Rg=16