Given f(x)=∫0x2t3+1dtf(x) = \int_{0}^{x^2} \sqrt{t^3 + 1} dtf(x)=∫0x2t3+1dt, find f′′(1)f''(1)f′′(1).
222\sqrt{2}22
626\sqrt{2}62
424\sqrt{2}42
828\sqrt{2}82