Given f(x)=x+ax−af(x) = \frac{x + a}{x - a}f(x)=x−ax+a (for a>0a > 0a>0, x≠ax \neq ax=a), find f(f(x))f(f(x))f(f(x)).
xxx
x+ax−a\frac{x + a}{x - a}x−ax+a
2xx2−a2\frac{2x}{x^2 - a^2}x2−a22x
−x-x−x