Given f(x)=cos(kx)−1x2f(x) = \frac{\cos(kx) - 1}{x^2}f(x)=x2cos(kx)−1, find kkk such that limx→0f(x)=−8\lim_{x \to 0} f(x) = -8limx→0f(x)=−8.
k = 2
k = 4
k = 8
k = 16