Given f(x)=ax+bcx+df(x) = \frac{ax+b}{cx+d}f(x)=cx+dax+b, find f′′(x)f''(x)f′′(x).
2c(bc−ad)(cx+d)3\frac{2c(bc-ad)}{(cx+d)^3}(cx+d)32c(bc−ad)
bc−ad(cx+d)2\frac{bc-ad}{(cx+d)^2}(cx+d)2bc−ad
ad−bc(cx+d)2\frac{ad-bc}{(cx+d)^2}(cx+d)2ad−bc
000