Given f(x)=(3x−1)2f(x) = (3x-1)^2f(x)=(3x−1)2, find f′(x)f'(x)f′(x) using the chain rule.
6(3x−1)6(3x-1)6(3x−1)
2(3x−1)2(3x-1)2(3x−1)
18x−618x-618x−6
9x−39x-39x−3