Ononot — Given f(n) = f(n-1) + f(n-2) with f(0)=2 and f(1)=1 (Lucas s

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Recursionhard

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Given $f(n) = f(n-1) + f(n-2)$ with $f(0)=2$ and $f(1)=1$ (Lucas sequence), what is $f(4)$ ?