Given ∣x12x∣=2\begin{vmatrix} x & 1 \\ 2 & x \end{vmatrix} = 2x21x=2, find the possible values of xxx.
x=1,−1x = 1, -1x=1,−1
x=2,−2x = 2, -2x=2,−2
x=0x = 0x=0
x=2,−2x = \sqrt{2}, -\sqrt{2}x=2,−2