Given an=an−1+6an−2a_n = a_{n-1} + 6a_{n-2}an=an−1+6an−2 with a0=0,a1=5a_0 = 0, a_1 = 5a0=0,a1=5, what is the closed-form expression for ana_nan?
an=3n−(−2)na_n = 3^n - (-2)^nan=3n−(−2)n
an=5(3n−(−2)n)a_n = 5(3^n - (-2)^n)an=5(3n−(−2)n)
an=3n+(−2)na_n = 3^n + (-2)^nan=3n+(−2)n