Given an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2, which of these initial conditions makes an=n2na_n = n 2^nan=n2n?
a0=0,a1=2a_0 = 0, a_1 = 2a0=0,a1=2
a0=1,a1=2a_0 = 1, a_1 = 2a0=1,a1=2
a0=0,a1=1a_0 = 0, a_1 = 1a0=0,a1=1
a0=1,a1=0a_0 = 1, a_1 = 0a0=1,a1=0