Given an=3an−1−2an−2a_n = 3a_{n-1} - 2a_{n-2}an=3an−1−2an−2 with a0=2,a1=3a_0 = 2, a_1 = 3a0=2,a1=3, find the closed-form expression.
an=2n+1a_n = 2^n + 1an=2n+1
an=2n+2a_n = 2^n + 2an=2n+2
an=2n+na_n = 2^n + nan=2n+n
an=3n−1a_n = 3^n - 1an=3n−1