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Recurrence Relationseasy
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Given an=3an−1−2an−2a_n = 3a_{n-1} - 2a_{n-2}an​=3an−1​−2an−2​, if a0=0a_0=0a0​=0 and a1=1a_1=1a1​=1, what is a2a_2a2​?