Given A={x:x is an even prime number}A = \{x : x \text{ is an even prime number}\}A={x:x is an even prime number} and B={x:x2−1=0}B = \{x : x^2 - 1 = 0\}B={x:x2−1=0}. Which of the following is true?
A={2}A = \{2\}A={2}
B={1,−1}B = \{1, -1\}B={1,−1}
A∩B=∅A \cap B = \emptysetA∩B=∅
A∪B={−1,1,2}A \cup B = \{-1, 1, 2\}A∪B={−1,1,2}