Given A={x∈R:x2−1≤0}A = \{x \in \mathbb{R} : x^2 - 1 \leq 0\}A={x∈R:x2−1≤0} and B={x∈R:x2−4x+3≤0}B = \{x \in \mathbb{R} : x^2 - 4x + 3 \leq 0\}B={x∈R:x2−4x+3≤0}, find AΔBA \Delta BAΔB.
[1,3][1, 3][1,3]
[−1,1)∪(1,3][-1, 1) \cup (1, 3][−1,1)∪(1,3]
(−1,1)∪(1,3)(-1, 1) \cup (1, 3)(−1,1)∪(1,3)
{1}\{1\}{1}