Given A=(4213)A = \begin{pmatrix} 4 & 2 \\ 1 & 3 \end{pmatrix}A=(4123), find the matrix PPP such that A=PDP−1A = PDP^{-1}A=PDP−1 where DDD is a diagonal matrix.
P=(2−111)P = \begin{pmatrix} 2 & -1 \\ 1 & 1 \end{pmatrix}P=(21−11)
P=(121−1)P = \begin{pmatrix} 1 & 2 \\ 1 & -1 \end{pmatrix}P=(112−1)
P=(112−1)P = \begin{pmatrix} 1 & 1 \\ 2 & -1 \end{pmatrix}P=(121−1)
P=(−1112)P = \begin{pmatrix} -1 & 1 \\ 1 & 2 \end{pmatrix}P=(−1112)