Given A=(3102)A = \begin{pmatrix} 3 & 1 \\ 0 & 2 \end{pmatrix}A=(3012), find the eigenvalues by solving the characteristic equation det(A−λI)=0\det(A - \lambda I) = 0det(A−λI)=0.
λ=1,2\lambda = 1, 2λ=1,2
λ=3,2\lambda = 3, 2λ=3,2
λ=0,3\lambda = 0, 3λ=0,3
λ=3,1\lambda = 3, 1λ=3,1