Given A=(2130)A = \begin{pmatrix} 2 & 1 \\ 3 & 0 \end{pmatrix}A=(2310) and B=(10−12)B = \begin{pmatrix} 1 & 0 \\ -1 & 2 \end{pmatrix}B=(1−102), compute ABABAB.
(1230)\begin{pmatrix} 1 & 2 \\ 3 & 0 \end{pmatrix}(1320)
(203−1)\begin{pmatrix} 2 & 0 \\ 3 & -1 \end{pmatrix}(230−1)
(30−22)\begin{pmatrix} 3 & 0 \\ -2 & 2 \end{pmatrix}(3−202)
(1023)\begin{pmatrix} 1 & 0 \\ 2 & 3 \end{pmatrix}(1203)