Given a 2×22 \times 22×2 matrix AAA with eigenvalues λ1=2\lambda_1 = 2λ1=2 and λ2=−1\lambda_2 = -1λ2=−1, is AAA diagonalizable? Why?
Yes, because both eigenvalues are real
Yes, because the two eigenvalues are distinct
No, because one eigenvalue is negative
Cannot determine without knowing the eigenvectors