For which value(s) of xxx is (x2−1)24=∣x2−1∣\sqrt[4]{(x^2 - 1)^2} = |x^2 - 1|4(x2−1)2=∣x2−1∣?
All real xxx
x≥1x \geq 1x≥1 or x≤−1x \leq -1x≤−1
−1≤x≤1-1 \leq x \leq 1−1≤x≤1
x=±1x = \pm 1x=±1 only