For which ppp does ∑n=2∞1n(lnn)p\sum_{n=2}^{\infty} \frac{1}{n(\ln n)^p}∑n=2∞n(lnn)p1 converge?
p>1p > 1p>1
p≤1p \leq 1p≤1
p>0p > 0p>0
Always diverges