For what zzz does arg(z)=arg(zˉ)\text{arg}(z) = \text{arg}(\bar{z})arg(z)=arg(zˉ)?
{z:Im(z)=0}\{z : \text{Im}(z) = 0\}{z:Im(z)=0}
{z:Re(z)=0}\{z : \text{Re}(z) = 0\}{z:Re(z)=0}
∣z∣=1|z|=1∣z∣=1
None