For what values of xxx does the series ∑n=1∞(x−3)nn2\sum_{n=1}^{\infty} \frac{(x-3)^n}{n^2}∑n=1∞n2(x−3)n converge?
2≤x≤42 \leq x \leq 42≤x≤4
∣x−3∣<1|x-3| < 1∣x−3∣<1
x>4x > 4x>4
∣x−3∣<2|x-3| < 2∣x−3∣<2