For what values of xxx does the series ∑n=0∞xn2nn!\sum_{n=0}^{\infty} \frac{x^n}{2^n n!}∑n=0∞2nn!xn converge?
(−2,2)(-2, 2)(−2,2)
(−1,1)(-1, 1)(−1,1)
(−∞,∞)(-\infty, \infty)(−∞,∞)
[0,2][0, 2][0,2]