For what value(s) of mmm does the system {y=x2−2x+1y=mx\begin{cases} y = x^2 - 2x + 1 \\ y = mx \end{cases}{y=x2−2x+1y=mx have exactly one real solution?
m=0m = 0m=0 only
m=0m = 0m=0 or m=−2m = -2m=−2
m=1m = 1m=1 or m=−1m = -1m=−1
m=0m = 0m=0 or m=2m = 2m=2