For two events AAA and BBB, P(A)=0.5,P(B)=0.4P(A) = 0.5, P(B) = 0.4P(A)=0.5,P(B)=0.4, and P(A∪B)=0.7P(A \cup B) = 0.7P(A∪B)=0.7. Are the events independent?
Yes, because P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
No, because P(A∩B)≠P(A)P(B)P(A \cap B) \neq P(A)P(B)P(A∩B)=P(A)P(B)
Yes, because P(A∩B)=0.2P(A \cap B) = 0.2P(A∩B)=0.2
Cannot be determined