For three events $A$, $B$, and $C$, the probabilities of individual events are $P(A) = P(B) = P(C) = 0.4$. The pairwise intersection probabilities are $P(A \cap B) = P(B \cap C) = P(A \cap C) = 0.15$, and the probability of all three occurring is $P(A \cap B \cap C) = 0.05$. Find the probability that exactly one of these three events occurs.