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Differential Equationshard
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For the Riccati equation dydx=1+x2−y2\frac{dy}{dx} = 1 + x^2 - y^2dxdy​=1+x2−y2, it is observed that y1(x)=xy_1(x) = xy1​(x)=x is a particular solution. If we substitute y=x+1vy = x + \frac{1}{v}y=x+v1​, what linear differential equation does v(x)v(x)v(x) satisfy?