For the recurrence an=2nn+1an−1a_n = \frac{2n}{n+1} a_{n-1}an=n+12nan−1 with a1=3a_1 = 3a1=3, find a5a_5a5.
161616
485\frac{48}{5}548
121212
3⋅256\frac{3 \cdot 2^5}{6}63⋅25