For the recurrence an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2 with a0=0,a1=2a_0 = 0, a_1 = 2a0=0,a1=2, find a3a_3a3.
16
24
32
40