For the recurrence an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2, if a0=1a_0 = 1a0=1 and a1=4a_1 = 4a1=4, what is a2a_2a2?
121212
161616
888
444