For the piecewise function f(x)={x2+2x≤14x−1x>1f(x) = \begin{cases} x^2 + 2 & x \leq 1 \\ 4x - 1 & x > 1 \end{cases}f(x)={x2+24x−1x≤1x>1, does limx→1f(x)\lim_{x \to 1} f(x)limx→1f(x) exist?
Yes, and equals 333
No, because left and right limits differ
Yes, and equals 444
Yes, and equals 555