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Eigenvalues & Eigenvectorseasy
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For the matrix A=(3001)A = \begin{pmatrix} 3 & 0 \\ 0 & 1 \end{pmatrix}A=(30​01​), find a left eigenvector for eigenvalue λ=3\lambda = 3λ=3 (i.e., a row vector wT\mathbf{w}^TwT such that wTA=3wT\mathbf{w}^T A = 3\mathbf{w}^TwTA=3wT).