For the equation y′=2x(1+y2)y' = 2x(1+y^2)y′=2x(1+y2), solve with y(0)=0y(0)=0y(0)=0. What is the solution?
y=x2y = x^2y=x2
y=tan(x2)y = \tan(x^2)y=tan(x2)
y=tan(x)y = \tan(x)y=tan(x)
y=ex2y = e^{x^2}y=ex2