For the ellipse x2+4y2=16x^2 + 4y^2 = 16x2+4y2=16, find the coordinates of the foci.
(±23,0)(\pm 2\sqrt{3}, 0)(±23,0)
(±3,0)(\pm \sqrt{3}, 0)(±3,0)
(0,±23)(0, \pm 2\sqrt{3})(0,±23)
(0,±3)(0, \pm \sqrt{3})(0,±3)