For the differential equation y′+2y=4e−2xy' + 2y = 4e^{-2x}y′+2y=4e−2x, what is the correct general solution?
y=(4x+C)e−2xy = (4x + C)e^{-2x}y=(4x+C)e−2x
y=4xe−2x+Cy = 4xe^{-2x} + Cy=4xe−2x+C
y=2xe−2x+Ce−2xy = 2xe^{-2x} + Ce^{-2x}y=2xe−2x+Ce−2x
y=4e−2x+Cy = 4e^{-2x} + Cy=4e−2x+C