For matrix A=(4102)A = \begin{pmatrix} 4 & 1 \\ 0 & 2 \end{pmatrix}A=(4012) and eigenvalue λ=4\lambda = 4λ=4, find an eigenvector.
(10)\begin{pmatrix} 1 \\ 0 \end{pmatrix}(10)
(01)\begin{pmatrix} 0 \\ 1 \end{pmatrix}(01)
(12)\begin{pmatrix} 1 \\ 2 \end{pmatrix}(12)
(−14)\begin{pmatrix} -1 \\ 4 \end{pmatrix}(−14)