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Recurrence Relationshard
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For an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an​=4an−1​−4an−2​ with a0=2a_0 = 2a0​=2 and a1=8a_1 = 8a1​=8, the characteristic equation (r−2)2=0(r-2)^2 = 0(r−2)2=0 gives the general solution an=(c1+c2n)⋅2na_n = (c_1 + c_2 n) \cdot 2^nan​=(c1​+c2​n)⋅2n. What are c1c_1c1​ and c2c_2c2​?