For a Poisson distribution with mean λ=0.25\lambda = 0.25λ=0.25, what is the probability P(X=1)P(X=1)P(X=1)?
0.25×e−0.250.25 \times e^{-0.25}0.25×e−0.25
e−0.25e^{-0.25}e−0.25
0.75×e−0.250.75 \times e^{-0.25}0.75×e−0.25
1−e−0.251 - e^{-0.25}1−e−0.25