For a $4 \times 4$ Schur complement problem: Let $M = \begin{pmatrix} A & B \\ C & D \end{pmatrix}$ where $A$ is $2 \times 2$, $B$ is $2 \times 2$, $C$ is $2 \times 2$, $D$ is $2 \times 2$, and $A$ is invertible. The Schur complement is $S = D - CA^{-1}B$, with $\det(M) = \det(A)\det(S)$. If $\det(A) = 2$, $\det(B) = 3$, $\det(C) = -1$, and $\det(S) = 5$, what is $\det(M)$?