Find the smallest positive integer solution (x,y)(x, y)(x,y) to the equation x2−3y2=1x^2 - 3y^2 = 1x2−3y2=1.
(2,1)(2, 1)(2,1)
(7,4)(7, 4)(7,4)
(1,0)(1, 0)(1,0)
(4,2)(4, 2)(4,2)