Find the particular solution to y′=yy' = yy′=y with y(0)=4y(0) = 4y(0)=4.
y=4exy = 4e^xy=4ex
y=ex+3y = e^x + 3y=ex+3
y=4xy = 4xy=4x
y=e4xy = e^{4x}y=e4x