Find the particular solution to y′=exy' = e^xy′=ex with y(0)=5y(0) = 5y(0)=5.
y=ex+4y = e^x + 4y=ex+4
y=ex+5y = e^x + 5y=ex+5
y=5exy = 5e^xy=5ex
y=exy = e^xy=ex