Find the intersection of the line x=y=zx=y=zx=y=z and the plane x+2y+3z=12x + 2y + 3z = 12x+2y+3z=12.
(2,2,2)(2, 2, 2)(2,2,2)
(1,1,1)(1, 1, 1)(1,1,1)
(3,3,3)(3, 3, 3)(3,3,3)
(4,4,4)(4, 4, 4)(4,4,4)