Find ∫1x2−9dx\int \frac{1}{x^2-9} dx∫x2−91dx.
16ln∣x−3x+3∣+C\frac{1}{6}\ln|\frac{x-3}{x+3}| + C61ln∣x+3x−3∣+C
13arctan(x/3)+C\frac{1}{3}\arctan(x/3) + C31arctan(x/3)+C
ln∣x2−9∣+C\ln|x^2-9| + Cln∣x2−9∣+C
None