Find y′y'y′ for y=x+1xy = \frac{x+1}{\sqrt{x}}y=xx+1.
12x−12x3/2\frac{1}{2\sqrt{x}} - \frac{1}{2x^{3/2}}2x1−2x3/21
x−(x+1)/(2x)x\frac{\sqrt{x}-(x+1)/(2\sqrt{x})}{x}xx−(x+1)/(2x)
12x−1/2−12x−3/2\frac{1}{2}x^{-1/2} - \frac{1}{2}x^{-3/2}21x−1/2−21x−3/2
Both (a) and (c)