Find the volume of the region bounded by y=ex,y=0,x=0,x=1y = e^x, y=0, x=0, x=1y=ex,y=0,x=0,x=1 revolved about y=−1y=-1y=−1.
π(e2/2−2e+5/2)\pi(e^2/2 - 2e + 5/2)π(e2/2−2e+5/2)
π(e2/2+2e+5/2)\pi(e^2/2 + 2e + 5/2)π(e2/2+2e+5/2)
π(e2/2)\pi(e^2/2)π(e2/2)
π(e2−1)\pi(e^2-1)π(e2−1)